To generalize, for all inequalities with a < 0 and b > 0:
a < x < b
We can convert to
|x - (b+a)/2| < (b-a)/2, when |a| <= |b|
and
|x + (b+a)/2| < (b-a)/2, when |a| > |b|
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To generalize, for all inequalities with a < 0 and b > 0:
a < x < b
We can convert to
|x - (b+a)/2| < (b-a)/2, when |a| <= |b|
and
|x + (b+a)/2| < (b-a)/2, when |a| > |b|
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