A set formula that is perfect for probability question -  the Binomial Distribution
 
 Let p represent the probability of a success for one event (ie. flipping heads or rolling a 6) 
 Let n represent the total number of observed events (ie. coin flips or dice rolls) 
 Let k represent the desired number of successes (ie. number of heads or number of rolled 6's) 
 
 Using the binomial, we can quickly calculate the probability of k successes out of n events... 
 
 P(k) = nCk * p^k * (1-p)^(n-k) 
 
 Example 1:  What is the probability of flipping exactly 6 heads out of 10 coin flips? 
 
 P(6 heads) = 10C6 * (1/2)^6 * (1/2)^4 = 210/1024 = 105/512 
 
 Example 2:  What is the probability of rolling exactly 2 sixes with three dice? 
 
 P(2 sixes) = 3C2 * (1/6)^2 * (5/6)^1 = 15/216 = 5/72 
 
 The numerator of each answer (before simplification) will always  represent the number of WAYS to perform the k successes.  Obviously you  can perform the binomial for any number of successes and then add them  up as needed.  Also, notice that for k = 0, the binomial simplifies to  (1-p)^n, which means that for k >= 1, we use 1 - (1-p)^n 
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