x^n -a^n = (x-a)(x^(n-1) + x^(n-2) + .......+  a^(n-1) ) ......Very useful for finding multiples .For example (17-14=3  will be a multiple of 17^3 - 14^3)
For more study materials/ Vedic Maths tricks/ Practice tests : www.tutioncentral.com
 Also visit: http://jackofinterviews.blogspot.com/
 Facebook page: https://www.facebook.com/pages/TutionCentral
 CAIIB/JAIIB Pages- https://www.facebook.com/pages/Tutioncentral-CAIIB-JAIIB
 https://www.facebook.com/pages/IBPS-Banking-Tutioncentralcom
