If n is an integer from 1 to 96 (inclusive), what is the probability for n*(n+1)*(n+2) being divisible by 8?
A. 25%
B 50%
C 62.5%
D. 72.5%
E. 75%
For Detailed Answers..
N=n*(n+1)*(n+2)
N is divisible by 8 in two cases:
When n is even:
No of even numbers (between 1 and 96)=48
AND
When n+1 is divisible by 8. -->n=8p-1 --> 8p-1<=96 --> p=12.3 --> 12 such nembers
Total=48+12=60
Probability=60/96=0.62
Answer: C