If n is an integer from 1 to 96 (inclusive), what is the probability for n*(n+1)*(n+2) being divisible by 8?

A. 25%

B 50%

C 62.5%

D. 72.5%

E. 75%

For Detailed Answers..

N=n*(n+1)*(n+2)

N is divisible by 8 in two cases:

When n is even:

No of even numbers (between 1 and 96)=48

AND

When n+1 is divisible by 8. -->n=8p-1 --> 8p-1<=96 --> p=12.3 --> 12 such nembers

Total=48+12=60

Probability=60/96=0.62

Answer: C