**Question: **There is a number that is 5 times the sum of its digits. What is this number? Answer is not0.

**Answer:**

The number is 45, simply because

45 = 5 * (4 + 5)

How does one find this number?

Let T be the digit in the tens place and U be the digit in the units place. Then, the

number is 10*T + U, and the sum of its digits is T + U.

The following equation can be readily written:

10*T + U = 5*(T + U) or

10*T + U = 5*T + 5*U or

5*T = 4*U

Thus, T / U = 4 / 5

Since T and U are digits, T must be 4 and U must be 5.

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